Question

Triangle ABC is an isosceles triangle. Side CB is 12 feet 4 inches long. Sides AB and AC are each 0.75 of this length. What is the perimeter of triangle ABC?

Answer 1

Well, here we go:

You know that 1 ft = 12 inches, so 12 ft = 144 inches + 4 inches = 148 Inches = CB

Now, that AB and AC = .75CB each just find that.

So you know that AB = .75CB
and: AC = .75CB

And You know that P = AB + CB + AC = .75CB + CB + .75CB = 2.5CB

So in the end we get perimeter = P = 2.5CB And we get 2.5*148 = 370 inches

So P = 370 Inches: Which means that P = 30ft & 10 inches.

Answer 2

alternatively,

12 ft 4 in = 12*12 in + 4 in = 144 in + 4 in = 148 in

so

CB = 148 in

Answer 3

take 3/4 of this to get

(3/4)*148 = 111

so AC = 111 inches and AB = 111 inches