Question

For the equation -2x^2 + x + j = 0, find all the values of j such that the equation has two real number solutions. Show your work and justify your answer.

Answer 1

do you know when a quadratic has two real roots ?

Answer 2

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Answer 3

When it's greater than 0?

Answer 4

no so this depend how the discriminant

do you know it how ?

Answer 5

formula for discriminant = ???

Answer 6

b^2-4ac

Answer 7

yes right

so than do you know how depend the roots of a quadratic from discriminant ?

so when D > 0
D = 0
D < 0

Answer 8

D > 0 2 Roots
D = 0 1 Root
D < 0 0 Root

Answer 9

not is exactly

Answer 10

so when D > 0 has two real roots greater than zero different
D = 0 two real roots equals
D < 0 havnt real roots

ok ?

Answer 11

Ooh alright I understand it

Answer 12

so than now you can solve sure ,yes ?

Answer 13

Yes thank you!

Answer 14

was my pleasure

good luck

yw

bye