Question

Tickets for a football game cost $8 and $12. If 480 tickets were sold for total reciepts of $4620, how many of each type of ticket were sold?

Answer 1

So set up two equations:

Ticket A (8 dollar) and ticket B (12 dollars)

Then set up two equations like so:

A+B = 480 &
8A + 12B = 4620

Now solve this as a system of equations.

Answer 2

sorry im dumb how do i solve system of equations? lol

Answer 3

well, set the first equation to A = 480 -B

Now put this in the second equation to do:

8(480-B) + 12B = 4620
And solve for B, once you have B, put it in the first one and solve for A.

Answer 4

THANKS ZELDA!

Answer 5

No problem, remember to mark it best response though.