Question

Lines and Planes. Can anyone help with this problem? Find the distance between (1,5,-2) and line x = 4t - 2, y = 3 and z = 1 - t.

Answer 1

@stamp

Answer 2

The distance D from point P to the plane is equal to the absolute value of the scalar projection of b onto the normal vector n = <a, b, c>

Answer 3

\[D=\left| vectorPQ \right|\sin\]
\[=\left| PQ x U \right|/\left| u \right|\]