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can anyone solve: (a^2-a-2)*(a^2+2a+1) ???
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(A+1)(A^3-3a-2)
It cant be factored any further utalizing real numbers.
so it can be factored with imaginary numbers?
I believe so. You can attempt but imaginary numbers arnt my strong suit sorry.
mine either thats cool
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(a+1) (a-2) * (a+1) (a+1) = 0 (a+1)^3 (a-2) =0 (a+1)^3 = 0 and (a-2)= 0 so a = -1 and a = 2
hey thanks camila! i would give u guys both medals.. but mike was first
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