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determine the type of number that the solution x^2+2x+5=0
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b^2 - 4ac = 0, 1 real solution b^2 - 4ac > 0, two real solutions b^2 - 4ac < 0, two complex solutions
the type of number would be 1 real solution?
b^2 - 4ac, a = 1, b = 2, c = 5 b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16
so what type of number is it. this may be a ridiculous question but im very confused
Since you see that b^2 - 4ac is a negative number, that means the solutions to this equation are two complex (imaginary) numbers.
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ok i get it now thanks:)
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