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OpenStudy (anonymous):
ab+2a+3b+6 grouping
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OpenStudy (anonymous):
please help me and show me how u did this
OpenStudy (anonymous):
Factor the first two terms and then last two terms The first two have 'a' in common so you can factor that out a(b+2) last two have a gcf of 3 so you take that out 3(b+2) so now ya got a(b+2)+3(b+2) turns into (a+3)(b+2)
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