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Mathematics 18 Online
OpenStudy (anonymous):

ab+2a+3b+6 grouping

OpenStudy (anonymous):

please help me and show me how u did this

OpenStudy (anonymous):

Factor the first two terms and then last two terms The first two have 'a' in common so you can factor that out a(b+2) last two have a gcf of 3 so you take that out 3(b+2) so now ya got a(b+2)+3(b+2) turns into (a+3)(b+2)

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