Question

y varies directly as the square of x. When x = 3, y = 18. What is the value of y when x = 4?
A.12
B. 16
C. 24
D. 32

Answer 1

y1/x1^2=y2/x2^2
=>
18/9=y/16

Answer 2

?

Answer 3

solve for y

Answer 4

2=y/16

Answer 5

?

Answer 6

so y=16*2=32

Answer 7

Thanks!

Answer 8

np