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If cos theta = -5/13 and sin theta > 0, then tan theta is ?
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From sin theta> 0, we can draw out a graph to see where it might be. Sin theta is y/r where r is the radius. The r (radius) must be positive because distance is never negative. If sin theta>0, that means y cannot be negative or else sin theta will be negative. Therefore, our "triangle" is either in quadrant I or II|dw:1360627130554:dw|
Then, we know that cos theta is x/r, where r is the radius. Then, we can determine the length and xcor of the outreaching point|dw:1360627258061:dw| Also, we can determine the remaining side by using Pythagorean theorum. Now, you input the values for tan theta to get your answer.
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