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Mathematics 20 Online
OpenStudy (anonymous):

2. What are the values of a and b

OpenStudy (anonymous):

OpenStudy (anonymous):

a= go b= niners :D

OpenStudy (anonymous):

\[b^2+10^2 =(a+8)^2\] and also \[a^2+6^2=b^2\] thus \[a^2 +6^2 +10^2 = (a+8)^2\] can you find a?

OpenStudy (anonymous):

ummmm no not really ?

jimthompson5910 (jim_thompson5910):

alternatively, you can solve this for 'a' 8/6 = 6/a

jimthompson5910 (jim_thompson5910):

once you have the value of 'a', you can use it to find b

OpenStudy (anonymous):

they are jut pthagorean triples. look at pic

OpenStudy (anonymous):

Thanks you guys i figured it out C;

OpenStudy (anonymous):

kk

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