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2. What are the values of a and b
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a= go b= niners :D
\[b^2+10^2 =(a+8)^2\] and also \[a^2+6^2=b^2\] thus \[a^2 +6^2 +10^2 = (a+8)^2\] can you find a?
ummmm no not really ?
alternatively, you can solve this for 'a' 8/6 = 6/a
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once you have the value of 'a', you can use it to find b
they are jut pthagorean triples. look at pic
Thanks you guys i figured it out C;
kk
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