Question

factor grouping mn - 4m - 5n + 20

Answer 1

try factorising the first two with each other and the last two with each other

Answer 2

in those pairs take out the HCF

Answer 3

is the grouping like this (mn-4m)(5n+20)

Answer 4

is that how u group it

Answer 5

not quite

Answer 6

then how do u do it

Answer 7

\[(mn-4m)-(5n-20)\]
\[m(n-4)-5(n-4)\]
\[(m-5)(n-4)\]

Answer 8

does that make sense?