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a2 - a - 20
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\[a^2-a-20\]?
what do you need to do?
factorize?
put it in grouping
\[(b+p)(b+q)=b^2+(p+q)b+pq\] you need to find \(p,q\) such that \(p+q=-1\) and \(pq=-20\)
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inotherwords; you need to find the two numbers that add to give negative one and multiply to give negative twenty
pairs of factors of negative twenty are\[-20=(\pm1)(\mp20),(\pm2)(\mp10),(\pm4)(\mp5).\] can you find the pair that add to give negative one?
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