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solve on the interval [0,2pi) 2cos^2x-5cosx+2=0
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i cant tell if i should be verifying or simplifying..?
you need to solve...means find values of x. let cos x = y then you get a quadratic equation, which u can sove ?
*solve
cosx=y? where does y come in?
It's not a quadratic, but you can treat it like one. Let u=cox Then 2u^2 - 5u + 2 = 0 Factor. Substitute back, and solve.
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OHH okay that makes a lot more sense, ill try that out
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