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Physics 18 Online
OpenStudy (anonymous):

Is this right? I just wanted to make sure. http://i50.tinypic.com/21cvae9.jpg

OpenStudy (anonymous):

nope its not right... why woud you have i0 flowing there in that upper rightmost resistor? a part of i0 flows as i1.. in the upper left resistor.. hence the rest of the current flows in the right one!

OpenStudy (anonymous):

Thanks, I had a feeling I was wrong, I wasn't sure how it broke up.

OpenStudy (anonymous):

I hope you understand now

OpenStudy (anonymous):

and infact thats a balanced Wheatstones network!..

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