Ask your own question, for FREE!
Physics 19 Online
OpenStudy (anonymous):

Is this right? I just wanted to make sure. http://i50.tinypic.com/21cvae9.jpg

OpenStudy (anonymous):

nope its not right... why woud you have i0 flowing there in that upper rightmost resistor? a part of i0 flows as i1.. in the upper left resistor.. hence the rest of the current flows in the right one!

OpenStudy (anonymous):

Thanks, I had a feeling I was wrong, I wasn't sure how it broke up.

OpenStudy (anonymous):

I hope you understand now

OpenStudy (anonymous):

and infact thats a balanced Wheatstones network!..

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!