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Mathematics 17 Online
OpenStudy (anonymous):

Confused.

OpenStudy (anonymous):

OpenStudy (anonymous):

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OpenStudy (experimentx):

use similarity to find AC

OpenStudy (anonymous):

AC= 16.8 ?

OpenStudy (anonymous):

3.8/5.6 = 11.4/x Cross Multiplication= 16.8

OpenStudy (mathstudent55):

Notice that your unknown is QC, not AC. If you call QC x, then the proportion you need is: 3.8/5.6 = 7.6/x

OpenStudy (mathstudent55):

The way you did it, you got AC = 16.8, which is correct but is not what you are being asked. To finish, you must do: QC = AC - AQ QC = 16.8 - 5.6 = 11.2

OpenStudy (experimentx):

woops ... sorry, I lost track of it ... that's how you do it.

OpenStudy (anonymous):

Oh....I thought they were asking for PQ! Thank you anyway

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