Question

How to solve y^2-2y-8=7 ?

Answer 1

first start by subtracting 7 from both sides

Answer 2

How would I go after getting 0=y^2-2y-8-7 ?
I was absent when learning this

Answer 3

you should then get a binomial equal to 0

from here, you can
a) factor
b) complete the square
c)use the quadratic equation ( i would avoid using this unless absolutely necessary)

Answer 4

well -8-7 = ?

Answer 5

-15?

Answer 6

ok so what you now have is
0=y^2-2y-15

Answer 7

how would i factor from there?

Answer 8

(x+a)(x+b)=x^2+(a+b)x+ab

so start by looking at factors of -15
i suggest you list them

Answer 9

basically a*b= -15
a+b=-2

in this particular case

solve for a and b

Answer 10

1,-15,15, -1, 3, -5, -3,-5

Answer 11

ok now which multiple pair, when added together will give you -2?

Answer 12

Oh I see that now! Its -5 and 3