Question

The equation of the tangent line to the curve y=x+√x at the point (16,20) is y = ?

Answer 1

slope of tangent line is dy/dx at given point

dy/dx = 1+1/(2sqrtx) at x=16
dy/dx = 1+1/8
dy/dx = 9/8

slope is 9/8
next solve for y-intercept by plugging in given point to equation: y=mx+b