if you had a problem that looked like this:
4,500=4,200+3%c
how would you get the c by it's self

Question

if you had a problem that looked like this:
4,500=4,200+3%c
how would you get the c by it's self

anonymous · Answer

do I subtract

texaschic101 · Answer

4500 = 4200 + .03c (3% = .03)
4500 - 4200 = .03c
300 = .03c (divide by .03 to get c by itself)

Can you take it from here ?

anonymous · Answer

4,500-3=4,200+3%c-3 would it look like this

texaschic101 · Answer

you do not subtract the .03 .... you divide by it.

anonymous · Answer

oh okay I am confussed about how it should look after I do that

texaschic101 · Answer

Let me show you the whole problem....
4500 = 4200 + 3%c (turn the 3% into .03)
4500 - 4200 = 4200 + .03c - 4200 (subtract 4200 from both sides)
300 = .03c (now divide by .03 to get c by itself)
300/.03 = .03c/.03
10,000 = c

check...
4500 = 4200 + .03c (sub 10,000 in for c)
4500 = 4200 + .03(10,000)
4500 = 4200 + 300
4500 = 4500 (correct)

Do you understand ?

anonymous · Answer

yeah thank you

texaschic101 · Answer

you are very welcome...thats what I am here for :)