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OpenStudy (anonymous):
I need help solving this system of linear equations using substitution A + C =1 -5A+B-4C=0 6A-3B+4C=1
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OpenStudy (anonymous):
you can replace \(C\) by \(1-A\) in the second and third equations, then solve those for \(A\) and \(B\)
OpenStudy (anonymous):
\[-5A+B-4(1-A)=0\]\[6A-3B+4(1-A)=1\]
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