Question

I need help solving this system of linear equations using substitution
A + C =1
-5A+B-4C=0
6A-3B+4C=1

Answer 1

you can replace \(C\) by \(1-A\) in the second and third equations, then solve those for \(A\) and \(B\)

Answer 2

\[-5A+B-4(1-A)=0\]\[6A-3B+4(1-A)=1\]