Question

Find all real solutions
(x+2)^2=(x-4)^2

Answer 1

first, expand for LHS and RHS be :
(x+2)^2=(x-4)^2
x^2 + 4x + 4 = x^2 - 8x + 16

Answer 2

move side all terms RHS to LHS :
x^2 + 4x + 4 - x^2 + 8x - 16 = 0
just combine the similar terms :
12x - 12 = 0
solve for x

Answer 3

thank you I forgot my special products and thought it was x^2+4= x^2 - 16

Answer 4

note :
(a+b) ^ 2 = a^2 + 2ab + b^2 and
(a-b) ^ 2 = a^2 - 2ab + b^2
welcome ..

Answer 5

:D

Answer 6

memorize it :D

Answer 7

o_- I shall