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What is the minimum value of N that will make this statement true: If we pick any N composite numbers from 1 to 1000, then we can find 2 numbers whose greatest common divisor is not 1.
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i think it is {no. of prime no between 1 to X} + 1 where X = previous highest integer of sqrt(1000) = 31 so N = {No. of prime no. between 1 to 31 (including 31)} + 1 = 11 + 1 =12 so N= 12
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