Question

Solve the equation on the interval [0, 2π). cos x + 2 cos x sin x = 0

Answer 1

ok then what?

Answer 2

thats the answer

Answer 3

You should explain a little...

Answer 4

(@Swaazy )

Answer 5

naaaaah

Answer 6

I like toast

Answer 7

Try to factor: you can factor out cos x

Answer 8

cos x(1+2sin x)=0

Answer 9

quit trippin . . .

Answer 10

ZeHanz = Afganistan PIMP

Answer 11

So cos x = 0 or 1+2sin x = 0

Answer 12

ok

Answer 13

don't lie . . .

Answer 14

dry your eye

Answer 15

@Swaazy look i asked for help not someone to annoy me

Answer 16

and here comes your mother with those two little guys.
Punched me in the belly and stepped on my feet, wauh slammed the bit* on the hard concrete

Answer 17

cos x = 0 or sin x = -½

Now try to remember what values of x will give cos x = 0 or sin x = -½...

Answer 18

The pimp was strong, the bit*h was gone, something was wrong I said what is going on?

Answer 19

@Swaazy you are now block thanks have a nice life

Answer 20

yo

Answer 21

@Shawna17: can you look up these values in a table?

Answer 22

how would I do that do you have a link?

Answer 23

You could use this one, see image

Answer 24

my choices are
A. 0, pi/2, 7pi/6, 3pi/2
B. pi/2, 7pi/6, 3pi/2,11pi/6
C 7pi/6, 11pi/6, 2pi
D. 7pi/6, 11pi/6

Answer 25

cos x = 0 gives pi/2 and 3pi/2
sin x = -½ gives 7pi/6 and 11pi/6

Answer 26

so it's B

Answer 27

Yup!