Question

I need help with the last 2 rows...
(8/3 and 4/3 rows)

Answer 1

@dumbcow

Answer 2

The point of intersection (8/3, y) occurs when you solve the system

60x+30y = 240
28x-28y = 0

for x and y

So all you need to do is pick either equation and plug in x = 8/3. Then solve for y

Answer 3

the constraints should be
\[y \le -2x+8\]
\[y \le -\frac{1}{2}x+6\]
\[y \ge x\]
the point (4/3 , y) occurs when the first 2 constraints intersect
plug in x=4/3 to get y

point (8/3, y) occurs when 1st and 3rd constraint intersect
plug in x=8/3 to get y

Answer 4

plugging (8/3) into 60x+30y = 240 gives me the same answer as just dividing 8 by 3...
2.7

Answer 5

60x+30y = 240

60(8/3)+30y = 240

480/3+30y = 240

160+30y = 240

30y = 240-160

30y = 80

y = 80/30

y = 8/3

So when x = 8/3, y is y = 8/3

Answer 6

yeah i put 2.6 and 2.7 as my answer earlier but it was "wrong"
...i guess i needa put my answer in as a fraction

Answer 7

yeah it looks like they want either fractions or integers

Answer 8

its because of rounding ... 8/3 = 2.666666666...

Answer 9

need help with the next one too

Answer 10

i got 5.3 and 77 (rounded)

Answer 11

i think i needa have the 5.3 in fraction form too

Answer 12

yeah keep everything as fractions

when you convert from fraction to decimals, you lose information about the number

as dumbcow is saying, 8/3 = 2.6666... but you said 8/6 = 2.6

but 2.6 = 26/10 = 13/5 which is clearly not the same fraction

similar errors occur with 2.7

Answer 13

would i put in 53/10 or no?

Answer 14

that gives me 5.3 but i rounded to 5.3... the answer was actually 5.3333333

Answer 15

5.3 is not 53/10

Answer 16

5.3333333... = 5 + 0.3333333... = 5 + 1/3 = 15/3 + 1/3 = 16/3

Answer 17

so 5.3333333... = 16/3

Answer 18

THANKS GUYS!

Answer 19

can you guys also help me here?
i have the answers filled in and they are correct but i was wondering a few things.
http://openstudy.com/users/mariomintchev#/updates/511d7890e4b03d9dd0c4567b