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OpenStudy (anonymous):
you have 10 different pencils and 8 different erasers. how many different pairs of pencils and erasers are possible
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OpenStudy (anonymous):
i sai d80. or its like 2268?
jimthompson5910 (jim_thompson5910):
80 is correct
OpenStudy (anonymous):
okay thanks!
jimthompson5910 (jim_thompson5910):
Number of combos = (number of pencils)*(number of erasers) Number of combos = (10)*(8) Number of combos = 80
jimthompson5910 (jim_thompson5910):
The best way to visualize this is with a table say you had 2 types of pencils with 3 types of erasers |dw:1360891458494:dw|
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