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If y=log a(3) simplify log a(27a^5) (this is original question btw)
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i think its 3y something
oh yes please explain how to do this step by step. I think i only needs one step though
Is this correct? \[y=\log_a 3\]
ill write full quesiton above
yes thats correct
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i worked it out up to 3log a(3a^5)
ok, so we have \[\log_a {27a^5}\] Use addition property of log to separate 27 and a^5
oh didnt think of that :P
pff silly me.... my bad
I think you can do it, solve it through and then post your answer. I'll check it
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wait if we seperate it would be 3log a 3 + log a a^5? 3log a 3 + log a 3a^5?
which one would it be?
first one, why do you have doubt?
mhm lol idk
3y + 5 is the answer? :D
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