Question

Help Please :)

Answer 1

A projectile is shot straight up from a height of 6 feet with an initial velocity of 192ft/second. Its height after t seconds is givin by h(t)=6+192(t) - 16(t)^2. After how many seconds does the projectile reach its maximum height? What is the maximum height? After how many seconds will the height be 518 Feet?

Answer 2

@seiga Do you know how to start the problem?

Answer 3

Set it equal to 0. Find what t is, then plug it back into the original equation for max height.

Answer 4

omg I'm sorry Noah this looks like Chinese to me haha im not good at math xD

Answer 5

Somegirl Thanks for trying :)

Answer 6

lol im not good at math..neither do i try to get it...its like a whole different world...and language lol....either way ill just google it...it should be theyr somewhere...ahhaa...forget it guyzz...thanks anyways @SomeGirl1999 @Noah16 thanks

Answer 7

yup any time :)

Answer 8

@Noah16 thanks tho lol

Answer 9

Yourwelcome sorry @seiga :)

Answer 10

@Noah16 ill skip it...doesnt matter...haha thanks both...

Answer 11

ok good :)