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find the real zeros of the given polynomial and their corresponding multiplicities. Use this information along with a sign chart to provide a rough sketch of the graph of the polynomial. Compare your answer with the result from a graphing utility. a(x)=x(x+2)2
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the first x is odd so the equation intersects at the o and the other one is at -2
The function is a(x)=x(x+2)². If you have to find the zeros, you have to solve x(x+2)²=0. What are the solutions?
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