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Three equilateral masses m are placed at the three corners of an eq. triangle of side a.Find the force exerted by this system on another particle of mass m placed at the mid point of a side.
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http://gyazo.com/0c7bcaa88b6ee9f2b299f78034e74a7c did everything in that solution,but what happened at the end? why did we divide by 3?just want to be sure..
@Vincent-Lyon.Fr
The answer is \(\LARGE\frac{4Gm^2}{3a^2}\)
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