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Mathematics 17 Online
OpenStudy (anonymous):

The time between 9 AM and 10 AM so that the 2 hands of clacks coincide is

OpenStudy (anonymous):

wouldn't this depend on how far the hour hand moves per a unit time through to 10 am

OpenStudy (anonymous):

because in clocks now adays ,the hour hand moves continuously... now if the clock hour hand didn't move till it hit 10, then it'd be 9:45

OpenStudy (anonymous):

well exact answer is 9:49 1/11

OpenStudy (anonymous):

that would make sense are you given a function or something?

OpenStudy (anonymous):

or was this just an interesting question you posted

OpenStudy (anonymous):

I feel i'm missing important data and too lazy to go find the ratios i need lol

OpenStudy (agent0smith):

It's too late to solve this right now, but your answer looks pretty close to spot on. If you look up clock-angle problem you'll find lots of similar problems.

OpenStudy (agent0smith):

https://sites.google.com/site/mymathclassroom/trigonometry/clock-angle-problems/clock-hands-on-top-of-each-other Here you go... 9:49 and 1/11... spot on!

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