The time between 9 AM and 10 AM so that the 2 hands of clacks coincide is
wouldn't this depend on how far the hour hand moves per a unit time through to 10 am
because in clocks now adays ,the hour hand moves continuously... now if the clock hour hand didn't move till it hit 10, then it'd be 9:45
well exact answer is 9:49 1/11
that would make sense are you given a function or something?
or was this just an interesting question you posted
I feel i'm missing important data and too lazy to go find the ratios i need lol
It's too late to solve this right now, but your answer looks pretty close to spot on. If you look up clock-angle problem you'll find lots of similar problems.
https://sites.google.com/site/mymathclassroom/trigonometry/clock-angle-problems/clock-hands-on-top-of-each-other Here you go... 9:49 and 1/11... spot on!
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