Question

Derive an expression for the G.field due to a uniform rod of Length L and mass M at a point on its perpendicular bisector at a distance d from the centre

Answer 1

\[\LARGE \frac{2GM}{\sqrt{4L^2+d^2}}\]
is what I got one term seems missing

Answer 2

again, seems like you didnt take the components right.
E will be given by dE= 2dE1 sintheta
where dE1=G(dm)/(d^2 + x^2) where dm=m/l dx
sintheta=d/(d^2 + x^2)
integrate with respect to x from 0 to l/2