Question

algebra 2 help please

Answer 1

Yes?

Answer 2

one sec

Answer 3

how to divide this

Answer 4

when dividing fractions ... multiply by reciprocal
\[\frac{\frac{x^{2}-4}{x-8}}{x-2} = \frac{x^{2}-4}{x-8}*\frac{1}{x-2} = \frac{x^{2}-4}{(x-8)(x-2)}\]

Answer 5

now factor the top and see what cancels

Answer 6

so is answer (x-2) (x+2 / ( x-8)?

Answer 7

almost ....the (x-2) cancels leaving
\[\frac{x+2}{x-8}\]