Question

\[\Delta V=V_b-V_a=\frac{\Delta U}{q_0}=-\int_{a}^{b}\vec{E}\cdot d\vec{l}\]

Answer 1

Is that what it means?

Answer 2

"For a finite displacement form point a to point b, the change in potential is..." (see equation above)
I'm trying to make a visual for this concept. I believe my drawing is wrong

Answer 3

"The potential difference \(V_b-V_a\) is the negative of the work per unit charge done by the electric field on a test charge when the test charge moves from point a to point b (along any path)."