Question

using elimination or substitution solve this: 2y^2+ 3x=33 and x+4y+7=0

Answer 1

Substitute " X=-(4Y+7) " into the other one

Answer 2

you'll get :2y^2-3(4y+7)=33
then 2y^2-12y-21-33=0
y^2-6y-27=0
(y-9)(y+3)=0
y=9or-3

Answer 3

x=-(4y+7)
so x=-(4x9+7)
or x=-(4x(-3)+7)

Answer 4

ans: x=-43,y=9
or x=5,y=-3

Answer 5

Thank you so much :)