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Is 36x^4-64x^2 a special case polynomial?
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Notice that 36x^4 is the square of 6x^2, and 64x^2 is the square of 8x, so you have a difference of two squares binomial.
Thanks that is a big help
Can you solve 36x^4-64x^2 for me? I'm confused
Do you need to factor it?
I think so? It just says to show my work.
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a^2 - b^2 = (a + b)(a - b) 36x^4 - 64x^2 First step is to try to factor a common factor: 4x^2(9x^2 - 16) = 4x^2(3x + 4)(3x - 4)
thanks, will you help me with another one?
sure. pls start a new post. i'll look for it
where do I do that? I can't see where to do it:(
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