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Algebra 10 Online
OpenStudy (anonymous):

6x^3(x-1)-3x(x-1) factor.

OpenStudy (anonymous):

3x(x-1) (2x^2-1)

OpenStudy (anonymous):

can you show work on how you did it just for this one

OpenStudy (anonymous):

?

OpenStudy (jennychan12):

she did factoring by grouping.

OpenStudy (anonymous):

= 3x [2x^2(x-1)-(x-1)] = 3x(x-1) (2x^2-1)

OpenStudy (anonymous):

x^3+4x^2+8x+32 factor four term polynomial by grouping

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