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use the quadratic formula to find the x-intercpets on the the graph of the equation y=x^2+8x-5
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For the equation of the form ax^2 + bx + c = 0, the x-intercepts will be \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
it say math processing error dr v
Do you have a = 1, b = 8 and c = -5?
so it would be 8/2(1)
Then it woud be x=4
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any thoughts
?? What did you do to get x = 4? With a = 1, b = 8 and c = -5, we have: \(x = \dfrac{-8\pm\sqrt{8^{2}-4(1)(-5)}}{2(1)}\)
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