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The tangent of the line of the curve y=x^3-6x^2-34x-9
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sorry I didn't finish the question. It should be: The tangent of the line of the curve y=x^3-6x^2-34x-9 has a slope 2 at two points on the curve. find the two points.
This one is a tad bit trickier
y' = 3x^2 - 12x - 34 2 = 3x^2 - 12x - 34 0 = 3x^2 - 12x - 32 0 = 3(x^2 - 4x - 8) 0 = x^2 - 4x - 8 Solve for the zeroes and those are the x values for which there is a slope of 2
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