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How can you write the expression with rationalized denominator? square root 3 – square root 6 over square root 3 + square root 6
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Multiply by the conjugate on the top and bottom of the fraction which is 3-\[\sqrt{6}\]
The conjugate is 3 - square root 6
which of these would be the answer? (–1 – 2 square root 18) over 3 (–3 – 2 square root 18) over 9 –3 + 2 square root 2 9 – 2 square root 18
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