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Calculate the restricted value, or values, for the equation below. (3/x+2) + (1/2x) =4/x+2
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denominator can't be zero
x cannot be equal to zero for the value of x you can solve this quadratic and by chance if you get 0 as answer you can leave it aside
\[\frac{ 3 }{ x+2}+\frac{ 1 }{2x}=\frac{ 4 }{ x+2 }\] this is the equation
domain is restricted only function becomes undefined dividing by 0 is undefined set each denominator equal to zero x+2 = 0 ---> x = -2 2x = 0 ----> x=0 The restricted x-values are -2,0
oh, okay. Thank you!
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