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Precalculus 13 Online
OpenStudy (anonymous):

A ball is hurled in the air such that its horizontal (x) and vertical (y) shifts are given by the functions x(t) = 20t and y(t) = 40t – 5t^2, where x and y are in meters and the time t is in seconds. What is the ratio of y to x at time t = 5 seconds?

OpenStudy (harsimran_hs4):

what`s the problem ..... quite simple just put in t = 5 and get x and y and take their ratio

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