Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Can anyone please help me with this question? 4^2x+3=1.

OpenStudy (goformit100):

its ease solve using Quadratic Basics...

OpenStudy (anonymous):

4^2x=-2

OpenStudy (anonymous):

log -2 base 4 = 2x

OpenStudy (anonymous):

\[4^{2x+3}=1\]

OpenStudy (anonymous):

this is my exact equation

OpenStudy (anonymous):

oh gotcha

OpenStudy (anonymous):

And also we have to make it sure that we are not using logarithms only exponential equations.

OpenStudy (anonymous):

sorry can't help you there

OpenStudy (anonymous):

hmmm ok

OpenStudy (anonymous):

anyone can help me here?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
1 day ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
1 day ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!