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Find dy/du, du/dx, and dy/dx. y = 2√u , u=9x+4
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\[\frac{dy}{du}=\frac{d}{du}[2\sqrt{u}]=\frac{1}{\sqrt{u}}\]
\[\frac{du}{dx}=\frac{d}{dx}[9x+4]=9\]
\[\frac{dy}{dx}=\frac{dy}{du}\times \frac{du}{dx}\] so multiply them together to get the answer
Thanks!
yw
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