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Find an equation of the line that is tangent to the graph of f and parallel to the given line. Function f(x) = x2 − x Line x + 3y − 6 = 0
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function \(f(x)=x^2-x\) had derivative \(f'(x)=2x-1\)
slope of \(x+3y-6=0\) is \(-\frac{1}{3}\)
set them equal and solve for \(x\)
2x-1=-1/3
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