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Mathematics
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Suppose F(x)=g(h(x)) . If g(2)=3 , g′(2)=2 , h(0)=2 , and h′(0)=6 find F′(0) .
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just diffrentiate thee function
similar to the last one \[F(x)=g(h(x))\] \[F'(x)=g'(h(x))\times h'(x)\] by the chain rule
\[F'(0)=g'(h(0))\times h'(0)\] fill in the numbers you know to get the answer you want
2*2*6=24 but it says my answer is incorrect
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