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Suppose F(x)=f(x)g(2x) . If f(1)=3 , f′(1)=1 , g(2)=2 , and g′(2)=5 , find F′(1) .
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oh no
need both the product and the chain rule, which is the whole point of this problem
\[F(x)=f(x)g(2x)\] \[F'(x)=f'(x)g(2x)+f(x)g'(2x)\times 2\]
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