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Simplify. f-1g-1
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@Darrius the problem is f^1g^-1
@campbell_st
\[f^1g^{-1} = \frac{f}{g}\]
ok... so negative powers indicate fractions so \[g^{-1} = \frac{1}{g} \] so the problem of \[f^1 g^{-1} means f \times \frac{1}{g}.... or..... \frac{f \times 1}{g}\]
Tell me if im wrong or not
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Simplified term of f-1g-1 is f-g-2**.
rong
all you need to do is simplify the numerator
Check the second one lol
thank yal can yal help me again
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im going to post it
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