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Find the equation of the circle with center at (3, 2) and through the point (5, 4).
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\[(x-h)^2+(y-k)^2=r^2\] you have \((h,k)=(3,2)\) you need \(r^2\)
find the square of the distance between the points \((3,2)\) and \((5,4)\) via \[r^2=(5-3)^2+(4-2)^2\]
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