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A telephone line hangs between two poles 14m apart in the shape of a catenary y=20cosh(x/20)-15, where x and y are measured in meters. (a) find the slope of this curve where it meets the right pole. (b) find the angle between the line and the pole.
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I found the derivative which is sinh(x/20) and plugged in 7 for part (a) which is about .35719 but i dont remember how to find the angle for part b
The slop of the curve where it meets the right pole would be f'(14), would it not? f'(14) ~ 0.7586|dw:1361433846652:dw|
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