Question

[(z-2)*(z+4)]/ [(z-3)*(z+4)]
@Directrix

Answer 1

Anyways, I think I have it. In the end it's just (z-2)/(z-3) right?

Answer 2

Well, I don't know what the corrected problem is. Could you post that? Just the entire problem as it should be.

Answer 3

\[\frac{ (z^3 + 4z^2 - 4z - 16) / (z + 2) }{ z^2 + z - 12 }\]

Answer 4

@Directrix ?

Answer 5

(z - 2)/(z - 3) where z is not equal to -2 and z is not equal to 3. That is my answer.