Question

Help me??

Answer 1

Given the quadrant of theta in standard position and a trigonometric function value of theta , find the exact value for the indicated function.

I, cos theta = 0.25; tan theta

Answer 2

\[\theta = \cos^{-1}(0.25)\]

Answer 3

\[\tan(\cos^{-1}(0.25))= use calculator\]

Answer 4

are you looking for \(\tan(\cos^{-1}(\frac{1}{4}))\)

Answer 5

there is a triangle with \(\cos(\theta)=\frac{1}{4}\)
find the "opposite" side via pythagoras
\[\sqrt{4^2-1^2}=\sqrt{15}\]

Answer 6

that tells you \(\tan(\theta)=\sqrt{15}\)

Answer 7

Thank You @satellite73

Answer 8

yw